UF FQUILIBKIUM OF A rvUTATlXCI MASS OF LlgUID. 
325 
Now 1 find 
f{()d° 48', 73° 52') = + -000191 ; /(G9° 50', 73° 52') = + -001319. 
/(69° 48', 73° 56') = - -001186 ; /(69° 50', 73° 56') = - -000031. 
ii.(69° 48', 73° 52') = + -001058 ; it. (69° 50', 73° 52') = - -000885. 
it3(69° 48', 73° 56') = + -000655 ; It. (69° 50', 73° 56') = — -000765. 
By interpolation we get the following results :— 
The Jacobian ellipsoid is given Ijy 
(y — 69° 48') - -59642 (sin-' k - 73° 52') + -33091 = 0. 
The vanishiiii'’ of the coefficient of stability is niven hv 
O 1/ O t/ 
(y - 69° 48') + -041625 (sin-i k - 73° 52') — 1-0890 = 0. 
In these equations the minute of arc is the unit. 
Solvino- them I find 
to 
y = 69° 48'-997 = 62° 49'-0, 
sin-V = 73° 54'-225 = 73° 54'-2. 
With these values 1 hnd that the three axes o, b, c, where abc = a’^ are 
^ = -650659, 
/, 
= -814975, 
a 
- = 1-885827. 
a 
The last place of decimals in these is certainly doubtful. 
The fornuda for w’ is given in (35). 
2 
Now T = - (p^) (pq), k = CK sin y, (c^) (ly) = kF. 
Then since a = c cos y, h = 
_ 24 A cot 7 — j ^ A-‘ + secW 
'lira 1 + A"-^- 
r 1- ^ 1 + ^-2 ^ se(.2.^ 
In this formula, E’, y, A must correspond with values interpolated amongst tliose 
used in obtaining the solution. 
From this I hud 
= -1419990 = -14200. 
'lirp 
