126 
DR S. CHAPMAN ON THE KINETIC THEORY OF A COMPOSITE 
Now 
(2H0) 
o du 0 dv 0 dw 0 _ R fdu 0 dv 0 0w,A o( 0 du t) dv 0 dw 0 \ 
dx dy 02 3 \0O3 dy dz ) 3 \ dx dy dz j 
1 di 
5 ^H.0 4.2 
I>n 06 
by (2-013), 
where also w T e have used the notation indicated by 
(2'11) 
Evidently we have 
( 212 ) 
r 
c =2 
du () 
0W O 
^xx " 
dx 
0?/ 
02 J 
^ c — 2 
dv 0 
0^0 
0t6 o 
dy 
02 
0X ’ 
c, = 2 
dw 0 
0M O 
9^0 
02 
06C 
3// 
C zz + C yj/+ Oz — 0 * 
By substitution from (2*10) into (2’09), we find that 
(2'13) 
rls^S) ^ = 5 -i“ | + (*+02*. U£ 
+ f ( 2 s + 5 ) V\C XX . 
•i(2s + 5)i-^ 
i/ A c/t 
If we divide both sides of this equation by 10.2 h u and assign the zero value to s, 
it becomes 
(2-14) 
A^mjU, 2 
1 fj_ 0 i 4 8 / 1 \ 
2 12/6,0 1 + 1 dt \2hJ 
s y i 1 5 6) I o r l 
3 2/6^0 0* 3/q '“J ' 
On adding to this the corresponding ?/ and 2 equations, the result is 
(2-15) 
a^c, 2 = 
\Pi dt 
There is a similar equation for the second set of molecules, and by addition of the 
two we get 
( 216 ) A (Jm,C.’+JmA 3 ) = 0 = |p a (A ^2 _J L 
the left-hand side being zero, since energy is conserved throughout molecular 
