54 
DR. S. CHAPMAN ON THE SOLAR AND LUNAR 
Table 0 (continued). 
Seasonal Terms (continued) 
1 
P 
-1 _ 
P» 
2100 
1 
(30a/— 160a/a 2 — 744a/) sin <5 cos 3 <5 
(5a/ + 24a.,) sin <5 cos <5--—a/a., sin <5 cos <5 (13 cos 3 <5—43 sin 3 <5) 
360 v 1 2160 * v 
+ 
1 
51,840 
a/ sin <5 cos (5 (191 sin 2 <5— 41 cos 2 <5) 
a/ sin <5 cos <5 (27 cos 3 <5 + 8 sin 3 <5) 
270 
P*' 1 = o> 
1 
700.48 
(145a/—690a/a 2 +48 . 83a/) sin <5cos 3 <1 
«/ = — a x sin <5 + —-— a x sin <5 (2a/ — 9a.d (2 sin 3 <5 —cos 2 <5) 
i. 63 1 1134 v 1 - /v ’ 
Pj= 0 
Pi 2 = ~ b «1 sill + 952 1 000 <T sin <5 (15a/- 64a 2 ) (8 sin 2 <5 + 3 cos 3 <5) 
PT 2 = 0 
»/ = —'— (5a/ + 24a,) sin <5 cos 8+ —--a/ sin 8 cos 8 (133 cos 3 <5 — 41 sin 3 8) 
^ 2160 ' 2 ii run 1 v 
311,040 
—!-— a/a., sin 8 cos <5(13 sin 2 <5 — 29 cos 2 8) 
12,960 ' 
H—— a ., 2 sin <5 cos 8 (cos 2 8 — sin 2 8) 
540 ' 
Pi = — n n \ i 0 a/ sin 8 cos 2 <5 + ~— a, a., sin <5 cos 2 <5. 
13,440 
3150 
We may now also take into account the second term in V, depending on longitude 
(cf. 55). On substituting this term in place of V in (52), and taking a — r = 2 (so 
that we consider only a semi-diurnal atmospheric oscillation of type Q/), the left-hand 
side is found to be 
<x 
(62) |K/KCtan 0 2 ^[(QQ/ — 4Q 3 1 )sin{(s + 2)£ — \ 0 — a}+ 2 Q 3 3 sin {(s +2)£ + X 0 — a}]. 
.5 = — a> 
When the conductivity is uniform it follows that the corresponding parts of 3ft, the 
current function, are as follows :— 
(63) 
jA-K/KU tan 0 [(27Q/ — 2 Q 3 1 ) sin (2t — \ 0 — a) + Q 3 3 sin ( 2 £ + A 0 — a)]. 
