discovered in New Zealand . 
EXPLANATION OF PLATES t AND II. 
105 
PLATE I. 
Fig. 1. Tibia of Moa, nearly perfect, 30 inches in length. 
a , a , girth 10J inches, bone at the end much broken and 
reduced in size. 
b , b y girth, over processes, 12£ inches. 
c, Cy girth, 51 inches; smallest part. 
dy deep muscular impressions. 
c, e, girth, 9 inches. 
Note. —The largest Tibia yet found measured 4 in. longer than this. 
Fig. 2. Femur of Moa, nearly perfect, length 13 inches. 
ff girth, 12J inches. 
g } g, reticulated muscular impressions, very numerous. 
iy iy girth, 73 inches. 
hy ky ditto, smallest part, 3J inches. 
?n, m, ditto, 11J inches. 
Obs.— I have seen a portion of a femur , the small part of which 
measured 8 inches in girth ! The one from which the drawing 
was taken, though not so large, was more perfect. 
Fig. 3. Tarsus of Moa , nearly perfect; length 10 inches, 
jpy p, girth, 9 inches. 
r, r, ditto, 4 inches. 
s, Sy ditto, 8 inches. 
PLATE II. 
Fig. I. Upper surface of fragment of pelvis and dorsal vertebrae of 
Moa , deeply indented with muscular impressions. 
a to by measures 9£ inches. 
Cy canal of medulla spinalis . 
dy outer edge of acetabulum . 
Obs .—This bone differs very considerably from such bones in other 
birds, in its peculiar carinated shape in that portion which must 
have formed the lower part of the back. It must have been 
also considerably larger when entire, as the whole of the upper 
ridge is much broken. 
Fig. 2. Under surface of Figure 1. 
a f a, a perfect part of bone, where, in the narrowest place, 
it measures 3 inches half-way across. 
by outer edge of acetabulum. 
Cy canal of medulla spinalis . 
