322 
MINUTES OF PROCEEDINGS OF 
(4) In what range would the velocity of a 9-in. shell be reduced 
from 1420 to 1240 f.s.? 
d? 
Here. reduced range = — s = *3183.?. 
w 
Now, corresponding to velocity 1240 in Table I. we find 
ft. 
2208-6 
Do., do., velocity 1420, 1251*1 
Subtracting, 957*5 = reduced range . 
Hence, *31835 = 957*5 ft., 
.*. 8 = 3000 ft., nearly. 
(5) The time of flight of a shell weighing 9 lbs., fired from the 9-pr. 
gun of 6 cwt., was observed to be 3*0 secs.; the muzzle velocity is 
known to be 1400 f.s. Find the striking velocity and the range. 
Here, reduced time tj = *9604 x 3 = 2*8812 secs. 
(where d = 2*94 and w = 9). 
Corresponding to velocity 1400 in Table II. we find 
secs. 
*8747 
Adding reduced time , 2*8812 
¥7559 
which corresponds to a velocity in the same table of 969 f.s., nearly. 
Hence, striking velocity = 969 f.s. 
Now to find range. 
( dp 1 \ 
— s\ = *96045. 
Corresponding to velocity 969 in Table I. we find 
ft. 
4608*1 
Do., do., velocity 1400, 1348*4 
3259*7 = reduced range. 
Subtracting, 
Hence, 
*96045 = 3259*7 ft., 
3 259 *7 QQQ/f ff 
•• *=^9604 = 3394ft ' 
= 1131*3 yds. 
Hence, range = 1131*3 yds. 
