MINUTES OF PKOCEEDINGS OF 
324 
Here, 
d* _ (-45)8 
w~~ -06857 
,n 
- x 100 = 295-3 
w 
2-953, 
Table I. for vel. 1353 = 1584 
ft. 
1879-3 = 
295-3 
1297 
vel. at 100 
2174-6 = 
295-3 
1246 
II 
200 
2469-9 = 
295-3 
1198 
II 
300 
2765-2 = 
295-3 
1153 
II 
400 
3060-5 = 
295-3 
1113 
II 
500 
3355-8 = 
295-3 
1075 
II 
600 
3651-1 = 
295-3 
1043 
II 
700 
3946-4 = 
295-3 
1017 
II 
800 
4241-7 = 
295-3 
994 
II 
900 
4537-0 = 
295-3 
974 
II 
1000 
4832-3 = 
295-3 
955 
II 
1100 
5127-6 = 
295-3 
937 
II 
1200 
5422-9 = 
295-3 
920 
II 
1300 
5718-2 = 
295-3 
904 
II 
1400 
6013-5 = 
889 
II 
1500 
If it is required to find the height of the 500-yd. trajectory at 
intervals of 100 yds., it is only necessary to compute the time of flight 
oyer these intervals. 
