533 — 
t = 34’5 C„ = -1,029 
r 
1,54080 
1,55538 
1,00946 
-0,946 
1,08 S 
D 
1,54810 
1.56299 
1,00962 
-0,962 
1,069 
b 
1,56651 
1,58245 
1,01011 
-1011 
1,017 
V 
1,58325 
1,60008 
1,01063 
-1,063 
0,968 
Solution IL 
11°2 
Cu = - 
-1,333 
r 
1,49173 
1,51165 
1,01335 
-1,335 
0,999 
D 
1.49687 
1,51722 
1,01359 
-1,359 
0.981 
b 
1,51025 
1,53160 
1,01414 
-1,414 
0,943 
V 
1,52292 
1,54485 
1,01440 
-1,440 
0.926 
t = 
18°2 
c v = - 
-1,342 
r 
1,48758 
1,50748 
1,01337 
-1,337 
1,004 
D 
1,49253 
1,41297 
1,01370 
-1,370 
0,980 
b 
1,50579 
1,52726 
1,01426 
-1,426 
0,941 
V 
1,51835 
1,54045 
1,01455 
-1,455 
0,923 
t = 
30 8 
Cy = • 
-1,450 
r 
1,47988 
1,49997 
1,01370 
-1,370 
1,038 
D 
1,48470 
1,50531 
1,01388 
-1,388 
1,043 
b 
1,49783 
1,51929 
1,01446 
-1,446 
1,003 
V 
1,51000 
1,53232 
1,01478 
-1,478 
0.981 
Solution III. 
t = 
13°2 
Cy-■ 
-1,065 
r 
1.44464 
1,45936 
1,01019 
-1,019 
1,043 
D 
1 44813 
1,46329 
1,01047 
-1,047 
1,017 
b 
1,45749 
1,47330 
1,01078 
-1,078 
0.988 
V 
1,46663 
1,48275 
1,01099 
-1,099 
0,969 
