THE ROYAL ARTILLERY INSTITUTION. 
211 
The following are the data then for the calculation of the centre of gravity 
in both cases :— 
Bengal Pieces. 
9-pr. lOcwt. 
a = 92", 
y? = 217-6 lbs. 
/= 308 „ 
W— 2489-5 „ 
Q = 449 ,, 
R = 30". 
24-pr. howitzer 10 cwt. 
a = 88", 
p = 205’5 lbs. 
/= 329 „ 
W = 2578 „ 
<2 = 449 „ 
R = 30". 
ML = 51"*25, 
NL = 123"*5, 
cot MNL = cot <A = = 2-4097561, 
51*25 
$ = 22°. 32'. 14"-7; 
sin a = — =^ = 0-3260870, 
a 92 
a = 19°. 1'. 53''. 
sina = - = m = 0-3409091. 
a 88 
a = 19°, 55'. 56". 
Substituting the above values in Equations V. 
308 
X= 92 cos 
a 
= 92 cos a x 
= 77' / -855. 
2489-5 + 449y 
2630-5 
X = 88 cos 
a(l 
329 
2578 + 4492 
= 88 cos a X 
= 73"-731. 
2698 
3027 
9-pr. 10 cwt. 
r= 30 + 30 
= 30 + 30 
= 34"-226. 
(308 — 217-6) cot cf>. cot a — 217*6 
2489-5 + 449 
631-53 — 217-6 
2938-5 
24-pr. howitzer 10 cwt. 
r=30 + 30 
= 30 + 30 
(329 — 205-5) cot <£ . cot a — 205*5 
2578 + 449 
820-68 — 205*5 
3027 
= 36"-097. 
