349 
To calculate the value of the product v A for an elementary gas 
for which the value A cu is known (see § 23.) we have to remem¬ 
ber that in this case 
v = pw (9) 
w being the valency of an atom; from formula (2), § 23., we obtain 
vA=z2wA cm: (10) 
the (sometimes troublesome) p being eliminated. 
We now proceed to give the values of vA in all cases in which (see 
§§ 16—23.) consistent values of the constant A have been obtained. 
Hydrogen H 2 (v = 2) 
A = 7,39 
vA = 14,78 
H 
00 
= 15,76 
8,35 
16,70 
7,70 . . . 
15,40 
8,37 
16,74 
7.59 . . . 
15,18 
8,31 
16,62 
7,52 . . . 
15,04 
8,58 
17,16 
7,36 . . . 
H72 
8,343 
16,686 
mean value: 
15,89 
Oxygen 0 2 
(v = 4) 
A = 3,76 
... V 
A = 15,04 
4 = 3,95 ... vA : 
= 15,80 
3,73 
14,92 
2,98 . . . 
11,92 
mean 
vA (last value omitted) = 15,25. 
Atmospheric 
Air ( v - 
= 5,582) 
A = 3,15 
... V 
A = 17,58 
4 = 3.02 . . . vA 
= 16,85 
3,18 
. . . 
17.74 
2,54 . . . 
14,18 
3,14 
17,52 
2,68 . . . 
14,98 
3,02 
16,85 
3,19 . . . 
17,82 
2,83 
• • • 
15,79 
2,93 . . . 
16 ; 36 
2,92 
16,29 
2,96 . . . 
16.48 
2,98 
16,63 
mean value: 
16,55 
Nitrogen N 2 
(® = 6) 
A = 4,09 
... V 
A = 24,54 
4 = 3,94 . . , vA 
= 23,64 
3,78 
22,68 
3,41 . . . 
20,46 
2,35 
14,10 
3,99 . . . 
23,94 
3,88 
23,28 
3,90 . . . 
23,40 
mean i 
>4 = 23,13 (third value omitted). 
Bulletin III. 
7 
