Mar. i, 1924 
Antisheep Amboceptor and Complement in Fowls 713 
Examination of Table II shows that there is a complement in some 
chicken sera capable of activating an antisheep hemolysin (rabbit), 
when the ingredients are added in the usual order. However, there is 
considerable variation in the complement content of the various samples 
of sera tested. 
TREATMENT oE SEDIMENT 
One-half cubic centimeter of resuspended sediment was added to each 
of a series of 6 tubes. To the first 5 were added gradually increasing 
quantities of complement (guinea-pig serum diluted 1 to 10). Two- 
tenths cubic centimeters of this dilution of guinea-pig serum represented 
one unit of complement. The sixth tube served as a control to detect 
the presence of complement in the sediment suspension. Saline was 
added to each tube to make the total volume equal 2 cc. Table III 
gives the amounts of the various elements used. 
All tubes were thoroughly shaken and placed in the incubator at 37 0 C. 
for one hour and then placed in the refrigerator over night. Table IV 
gives the results of each test. 
Table III .—Titration of amboceptor in chicken serum 
Tube No. 
1 
; i 
2 
3 
4 
5 
i 
6 
Suspended sediment. 
Complement ( 1 - 10 ).! 
Saline. j 
i 
j 
0 . 5 ! 
u 1 
* 2 1 
1,3 
\ 
M . O 
m ui 
O- 5 
.6 
.9 
i 
O* 5 
.8 
• 7 
o- 5 
1 . 0 
• 5 
O- 5 
. 0 
i-5 
Table IV .—The hemolytic action of gradually increasing quantities of guinea-pig serum 
on resuspended sediment 
0.5 cc. of resuspended sediment plus guinea-pig complement. 
Control. 
Complement (1-10). 
O. 2 
1 
1 
0. 4 
0. 6 
1.0 
0 
Bird No. 
1 
! 
.. . _ 
I. 
ci 0 
0 
0 
O 
a + 
O 
2. 
0 
0 
0 
0 ; 
4 
O 
3. 
0 
0 
0 
0 ! 
4 
0 
4. 
0 
0 j 
0 
0 
4 
O 
5. 
0 
i 
° ! 
0 
0 
+ 
O 
6. 
0 
O j 
0 
0 
4 
0 
7 . 
8 .«... 
0 
O 
0 
0 
4 
0 
0 
O 
0 
0 
4 
0 
0. 
0 
O 
0 
0 1 
1 + 
0 
10. 
0 
O 
0 
°! 
4 
0 
11. 
0 
O i 
0 
0 
1 4 
0 
12. 
0 
O 
0 
0 
4 
0 
13. 
0 
O 
0 
0 
4 
0 
14. 
0 
O 
0 
0 
4 
0 
15. 
0 
O 
0 
0 
4 
0 
16. 
0 
O 
0 
0 
4 
0 
17.. 
0 
O 
0 
0 
4 
0 
18. 
i 0 
O 
0 
0 
4 
0 
19. 
0 
O 
0 
0 
4 
0 
20 . 
0 
O 
0 
0 
4 
0 
21 . 
0 
O 
0 
0 
4 
0 
22 . 
0 
O 
0 
! 
0 
4 
0 
«+■= trace; o=ro hemolysis. 
