Am.  Jour.  Pharm. 
Jan  ,  1890. 
Note  on  Narceine. 
35 
This  is  demonstrated  by  the  following  experiments  : — 
A.  Experiments  with  t<j<j  Normal  Solutions. 
1.  Forty  cc.  diluted  hydrochloric  acid  are  neutralized  by  41*7  cc. 
NaOH  solution. 
2.  Forty  cc.  diluted  hydrochloric  acid,  after  saturation  with  nar- 
cotine,  are  neutralized  by  41*5  cc.  NaOH  solution. 
3.  Forty  cc.  diluted  hydrochloric  acid,  after  saturation  with  pa- 
paverine, are  neutralized  by  42*2  cc.  NaOH  solution. 
4.  Forty  cc.  diluted  hydrochloric  acid,  after  saturation  with  nar- 
ceine, are  neutralized  by  42*0  cc.  NaOH  solution. 
B.  Ecperiments  with  tV  Normal  Solution. 
5.  Ten  cc.  diluted  sulphuric  acid  are  neutralized  by  9*65  cc. 
NaOH  solution. 
6.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  268  mgrm. 
narcotine,  are  neutralized  by  9*65  cc.  NaOH  solution. 
7.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  300  mgrm. 
papaverine,  are  neutralized  by  9 '7  cc.  NaOH  solution. 
8.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  300  mgrm. 
narceine,  are  neutralized  by  9*7  cc.  NaOH  solution. 
C.  Experiments  with  other  Alkaloids  and  to  Normal  Solutions. 
9.  Ten  cc.  diluted  sulphuric  acid  are  neutralized  by  9'65  cc. 
NaOH  solution. 
10.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  250  mgrm. 
morphine,  are  neutralized  by  1*7  cc.  NaOH  solution. 
11.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  299  mgrm. 
codeine,  are  neutralized  by  0*6  cc.  NaOH  solution. 
12.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  308  mgrm. 
cinchonine,  are  neutralized  by  4"6  cc.  NaOH  solution. 
13.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  300  mgrm. 
ehinine,  are  neutralized  by  6*0  cc.  NaOH  solution. 
14.  Ten  cc.  diluted  sulphuric  acid,  after  dissolving  200  mgrm. 
strychnine-,  are  neutralized  by  3'9  cc.  JSTaOH  solution. 
While  the  weak  bases  possess  no  neutralizing  power  at  all,  the 
alkaloids  named  sub.  C.  neutralize  a  corresponding  part  of  the  strong 
acid,  as  well  as  the  NaOH  solution. 
Morphine. — C17H23N03-|-H20  =  303,  consequently  250  mgrm.  mor- 
phine =  7*69  cc.  NaOH  solution.  Therefore  in  experiment  10  C.  I 
must  have  a  quantity  of  uncombined  acid  corresponding  with  1*69 
cc.  NaOH  solution  ;  really  1*7  cc.  more  used. 
