34^  Rapid  Determination  of  Sulphuric  Acid,  ^^""-/^"f^^^^""^- 
NORMAL    SULPHURIC  ACID. 
Factor  0.137  =  for  sulphur. 
Interpolation  table  between  9  c.c.  and  11  c.c. 
BaSOi=  233. 5 
H2SO4  =49.05 
=  98.1 
cbcm  of  n/iH2S04  contains 
cbcm  of  n/iH2S04  contains 
2 
H2SO4  in  1000  c.c. 
9.0 
C.C.   1.05075  BaSOi 
9.0  c 
\c.o.44i45  H.SO4 
44.1450 
9.1 
"     1.062425  " 
9.1 
"  0.446355 
44-6355 
9.2 
"     1.07410  " 
9.2 
'  0.451260 
45.1260 
9-3 
"  1.085775 
9-3 
"  0.456165 
45-6165 
9.4 
"  1-09745 
9.4 
"  0.461070 
46.1070 
9.5 
1.109125 
9-5 
"  0.465975 
46.5975 
9.6 
"     1. 12080  " 
9.6 
'  0.47088  " 
47.0880 
97 
"  1-132475 
9-7 
"  0.475785 
47-5785 
9.8 
"  I-14415 
9.8 
"  0.480690    4  " 
48.0690 
9.9 
"  1-155825 
9.9 
"  0.485595 
48-5595 
lO.O 
"     1. 16749 
lO.O 
'  0.49050 
49.0500 
lO.I 
"  1-179175 
10. 1 
'  0.495405 
49-5405 
10.2 
1. 19085 
10.2 
"  0.50031 
50.0310 
10.3 
"     1.2025  " 
10.3 
'  0.505215 
50.5215 
10.4 
"     1. 2142  " 
10.4 
"  0.51012 
5  LOT  20 
10.5 
"  1.22587 
10.5 
'  0.515025 
51-5025 
10.6 
"  1-23755 
10.6  ' 
'  0.519930 
51-9930 
10.7 
1.24922 
10.7 
"  0.524835 
52.4835 
10.8 
"  1.26090 
10.8 
"  0.529740 
52.9740 
10.9 
"  1.272S7 
10.9 
'  0.534645 
534645 
I  I.O 
"  1.28428 
1 1.0 
'  0.539550 
53 -95 50 
BaS04  X  0.137  =  Sulphur. 
BaSOi  X  0.34286  =  Factor  =  Sulphur  trioxide. 
BaSO*  X  0.420  =  Factor  =  Sulphuric  Acid. 
To  multiply  factor  with  Barium  Sulphate  gives  either  S,  SO3  or  H2SO4. 
The  following  is  an  addition  to  the  interpolation  table : 
I. 
2. 
3- 
4- 
9.0  to  9.1 
9.9  to  lO.O 
lO.O  to  lO.I 
lo.i  to  10.2 
0.051917 
LI 56992 
1. 1 68667 
1. 180342 
0.053084 
Li58i^9 
1. 169834 
1. 181 5092 
0.054251 
LI 59326 
I.I7IOOI 
I  182676 
0.055418 
1.169493 
LI72I68 
L 183843 
0.056585 
1.161660 
I-I73335 
I.1850IO 
0.057752 
LI 62827 
I- 1 7450 
L186177 
0.058919 
1. 1 63994 
LI 75669 
1. 1 87344 
0.060086 
I.165161 
LI 76836 
I.1885II 
0.061253 
1. 1 66328 
1. 1 78003 
LI 89678 
0.06242 
1. 167495 
I.I7917 
1. 1 90845 
Example : 
it  has  been  found 
upon  using  10  c.c. 
of  H.SO^  that 
I -1 73335  BaSOj^^  by  weight,  was  obtained.  Upon  consulting  table  3 
this  denotes  that  the  solution  of  H^SO^  is  5/100  or  0.05  in  10  c.c.  too 
strong. 
