Exempel (Hxample) v = 5. 
19 
w fo) I 2 3 A 5 6 7 8 9 IO 20” per Sec. 
y go° 67.94 46.94 28.01 2 o* KOM 18.°9 26.% 31.% ZO, brt 
7 MAX, RIS) 11.°9 13.°6 17.°9 Bis (00) 26.00 THC) ING EO 3.°8 0.°8 
w 
W 5 4.7 3.9 Do 1.4 fo) 1.4 2.8 4.1 5.4 6.7 18.”2 per Sec, 
U 180° HOM? ngewe TAOMND TANS 50.02 54:05 58.%0 61.%0 Ot FOSS 
€ 90* none, rind nando 12807 39.°8 35:26 BORO 29.01 OM -naMo 
5. du ae sin U å w sin y å w sin Y 
dv W WwW? w? + v2—2 wv cos y 
Maximum haves, ligesom i foregaaende Tilfælde, naar The maximum is reached, as in the foregoing case, 
when 
å 2 wv Fe: 2wv 
=. eT ESO) SY = =a a 
7 ww 1 92? Y= a tp 
: ; : w 
og Maximumsværdien er ——, eller and the maximum value is gn OF 
p?—v? BP 
w 180 w 180 
Wex, do = =——.0 dv. Wax do = ===> da, 
w—0? 7 vi? gt 
Dk,  = by 
w O I 2 3 4 5 6 7 8 9 10 20” per Sec. 
dw 0 0 0 0 0 0 0 0 0 0 0 
We max. oO Do å 5.05 10.77 25.05 CO BUND Ober io OM 7.°6 Borat 
G du —w cos (Uu—y)  wecose  w(w—veosy) 
W Me 2000 
Maximum haves, naar sin y = 0 og The maximum is reached when sin y = 0, and 
; : w Å å 
Maximumsverdien er ——, naar y=0 W=w—v the maximum value is when y=0, W= w—v 
pv—v? ; W—V å 
ES , haar Yy= 1809 W = wt». 7 — when Y=180°W = wv. 
w-- v w+ v 
Ex. v = 5, y=0, det er Vinden ombord ret for- Ex. v = 5, y = 0, i.e. the wind, as felt on board, 
ind. being right ahead. 
w Oo I 2 3 4 5 6 7 8 9 10 20” per Sec. 
du max 1 2 3 5 6 7! 8 9 4 
dy o — [le lø "Ip =A co j2 IE få 2 [3 
W 5 4 3 2 I (0) I 2 3 4 5 15 
v = 5, y = 180°, det er Vinden ombord ret agter- | v = 5, y = 180°, that is, the wind, as felt on board, 
ind. | being right aft. 
du a 2 3 4 / 5 6 7 8 9 10 20 
7 ma o Ic fr Is fy f10 Hog [12 [1s [14 f15 25 
W 5 6 7 8 9 10 II 12 13 14 15 25 
3* 
