130 
Vi have saaledes Y —x = a, og | We have thus X —æ = a, and 
KW eg Tv U GAS | 
= ; = Xe— = 240. = 540 km. 
% GK Ok” a TE aa 0.09 Serge 
Heraf faaes (This gives) 
x 2 
Toppunktets Hoide = 0.9 + 0.149 = 1.049 m. Hojden 
af Punktet U = 
1.049 — H = 1.049 —0.485 = 0.564 m. 
Fra Punktet med Hastigheden U = 0.13 til Islands 
Kyst er Afstanden a lig 170 km, og ved Kysten Hastig- 
heden w lig 0.10 m. p.S. Den tilsvarende Parabel har sit 
Toppunkt søndenfor Island, og Axen vender opad. Med 
de samme Betegnelser som ovenfor findes 
X U  X-x U—u GR 
= —; = TENNE) 
Ge U x U 
JE = 1X = 0435) im, 
= 0.485 54 
U= ~ 
Altsaa (Hence) X = 567 + 170 = 737 km. 
gg = X == = MO = 240 = 300 km. 
300) 
== OI ; 
5 70 49 m 
The height of the vertex = 0.9 + 0.149 = 1.049 m. 
The height of the pomt U = 
1.049 — H = 1.049 —0.485 = 0.564 m. 
and at the coast the velocity 2 equals 0.10 metre per sec. 
The corresponding parabola has its vertex south of Iceland, 
and its axis pointing upwards. 
tions as above, we get 
With the same denomina- 
En Neate 
(Y=N 
jal = fk Wf X= 0655 im, 
0.10 
= WU), —— = 
100, 0.03 
567 km. 
BE | | = 0.655 rn) = O88 mn 
Då 
Højden ved Islands Kyst = 
0.564 — (0.655—0.387) = 0.564 —0.268 = 0.296 m. 
. Fores et Normalsnit fra Punktet A til Islands Øst- 
kyst, kan man regne med XY = 685 km, U = 0.065 
(Middel af Hastighederne nordenfor) og faar deraf H= 0.3007 
Meter. Dette stemmer med Islandskystens Højde over Ni- 
veautladen, beregnet fra Grønland af. Middel af begge 
er } (0.296 + 0.501) =0.299 Meter. Islandskystens Højde 
kan saaledes sættes til 0.3 Meter. 
Med et Punkt i Atlanterhavet som Centrum sønden- 
for Island ere Ligehøjdelinierne beregnede efter Afstanden 
til Island og til Irland med de respektive Værdier af 
H = 0.3 og 0.5 Meter. 
Den saaledes fundne Form af Vindfladen er frem- 
stillet i Kartet Pl. XXXIIT. Dens dybeste Parti AB 
ligger 0.8 Meter under Europas Kyst, 0.9 Meter under 
Grønlands Kyst, 0.5 Meter under Spidsbergens Kyst og 0.3 
Meter under Islands Kyst. 
5. Havvandets specifiske Vægt. 
Hvad Bestemmelsen af denne for Havets Bevægelse 
vigtige Factor angaar, henvises til H. Tornøes Afhandling 
i denne Generalberetning. 
De 1 Tornges Tabeller* 'givne Værdier af Havvandets 
1 Den norske Nordhays-Expedition. Chemi. H. Tornøe. 
2 LL. c. S. 59—64. 
The height at the coast of Iceland = 
0.564 — (0.655—0,387) = 0.564 —0.268 = 0.296 metre. 
If a normal section be drawn from the point A to 
the east coast of Iceland, we can calculate with X = 685 
kms, U = 0.065 (mean of velocities farther north); and 
obtam H = 0.3007 metre. This result agrees with that 
for the height of the coast of Iceland above the surface of 
level computed from Greenland. The mean of both is 
1 (0.296 + 0.301) = 0.299 metre. Hence, the height of the 
coast of Iceland may be taken at 0.3 metre. 
With a point in the Atlantic south of Iceland as 
centre, the {lines of equal height have been computed ac- 
cording to the distance from Iceland and from Ireland, 
and with the respective values of H = 0.3 and 0.8 metre, 
The form of the wind-surface thus found has been 
represented in the map, Pl. XX XIII. Its deepest part, 
A B, lies 0.8 metre beneath the coast of Europe, 0.9 metre 
beneath the coast of Greenland, 0.5 metre beneath the 
coast of Spitzbergen, and 0.5 metre beneath the coast of 
Iceland. 1 
5. Specific Gravity of the Sea-Water. 
As regards determining this factor, so important for 
the motion of the sea, the author refers to H. Tornge’s 
Memoir, published in this General Report. * 
The values given in Tornge’s Tables? for the specific 
1 
The Norwegian North-Atlantic Expedition. Chemistry. H. 
Tornge. ' 
| 2 
Ibid., p. 59—64. 
From the point with the velocity U = 0.13 to the — 
coast of Iceland, the distance a@ is equal to 170 kilometres; * 
