å 175 
Stat. No 304 305 306 — 308 345 347 340 
3 1.02785 1.02787 1.02785 1.02785 1.02785 1.02784 1.22782 
p 274.6538 274.6592 274.6538 274.6538 274.0538 274.6512 274.6458 
; S 0.0290 0.0209 0.0176 0.0192 0.0302 0.0343 0.0499 
P 274.683 274.680 274.671 274.673 274.684 274.686 274.696 
Stat. No 350 x51 ) V 393 Hy, "Hy Gy 
3 1.02774. 1.02761 1.02777 1.02781 1.02746 1.02741 1.02759 
P 274.6243 274.5893 274.0323 274.0431 274-5489 274.5355 274.5839 
Ss 0.0712 0.0874. 0.0592 0.0453 0.0977 0.1258 0.0829 
lp 274.696 274.677 274.692 274.688 274.647 274.661 274.667 
Værdierne for Ps, Pio 08 Piso ere afsatte i Kar- 
terne Pl. XLV, XLVI og XLVII, og derefter ere Iso- 
barerne trukne. 
For at finde det System af horizontale Bevægelser, 
altsaa Bevægelser 1 Niveaufladen, der svarer til Isobar- 
Systemet, kunde man gaa frem ligesom 1 Meteorologien, 
og anvende Formlerne tor retliniede æquidistante Isobarer, 
under Forudsætning af at Frictionen var proportional med 
Hastigheden. Kaldes Gradientkraften (w G i Meteorologien) 
G, Massen af en Kubikmeter Vand o, Afbojningsvinkelen 
mellem Gradientens Retning (lodret paa Isobaren, fra det 
højere mod det lavere Tryk) og Bevægelsens Retning ca, 
Jordens Omdrejningshastighed w, Bredden g, Frictionscoeffi- 
cienten k og Hastigheden i Meter per Secund wu, saa har 
man i saa Fald: - 
GP E ; 
—sina =2using.u 
S 
A 
= G8 C=. hh 
ro) 
S 
Kaldes Afstanden (i Meter) langs Gradienten ZYæ, og 
den dertil svarende Trykforskjel i Kilogram (henført til 
den virkelige Tyngde paa Stedet) Ap, 
saa har man 
Ap 
Do 
Da en Kubikmeter Kviksølv vejer 13595.9 Kilogram, 
og en Atmosfere er lg Trykket paa en Kvadratmeter af 
en Kviksolvsojle af 0.76 Meters Højde (ved 0° og Normal- 
tyngden), bliver, naar Trykket regnes 1 Atmosfærer, 
C= 
Ap's = 13595.9 x 0.76 Ap" = 10333 Ap". 
Kaldes Søvandets virkelige, af Sammentrykningen paa- 
virkede, Tæthed S, vejer en Kubikmeter Søvand 1000 8S 
Kilogram. 
Er gi; Normaltyngden, har man altsaa 
1000 S 
Q=—— 
G45 
Indsættes disse’ Verdier i Bevegelsesligningerne, 
faar man 
The values for Peo, Pio, and Piso are set off on the 
maps, Pl. XLV, XLVI, and XLVII, and the isobars 
drawn accordingly. 
In order to find the system of horizontal motions, or 
the motions at the surface of level corresponding to the 
isobar-system, one might proceed as in meteorology, and 
apply the formule for straight equidistant isobars, assum- 
ing the friction proportional to the velocity. Now, if 
we call the force of the gradient (uw G in meteorology) 
G, the mass of a cubic metre of water o, the angle of 
deviation between the ‘direction of the gradient (perpendic- 
ular to the isobar, from the higher to the lower pressure) 
and the direction of the motion «, the angular velocity of 
the rotation of the earth w, the latitude g, the friction- 
coefficient Æ, and the velocity in metres per second wu, then 
cae : 
sma=2ousngp.u 
Q 
G 
=cosa=k.u 
Q 
Now, if we call the distance, in metres, along the 
gradient A\x, and the difference in pressure corresponding 
to it, in kilogrammes (referred to the true gravity at the 
place), Ap, 
we have 
_ Apts 
~ Lan 
As a cubic metre of mercury weighs 13595.9 kilo- 
grammes, and an atmosphere is equal to the pressure on a 
square metre of a column of 0.76 metre 
height (at O° and standard gravity), then, assuming the 
ke) ke) 2 ? ke) 
pressure to be computed in atmospheres, 
Apt = 13595.9 x 0.76 Ap" = 10333 Ap". 
Calling the actual density of sea-water, acted on 
by compression, S, a cubic metre of sea-water weighs 
1000 S kilogrammes. Å 
With gi; as the standard gravity, we have therefore 
1000 S 
OE 
045 
If these values be substituted into the equations of 
G 
mercury, in 
motion, we get 
