A 
the magnitude of the angle of projection (necessary for finding from the table the 
value of a) will be found to be : 
dy =4° 27. 
From the table O== OOO, 
and we calculate 
SSG 0 OOS y= TIO 
We obtain the value of w, corresponding to the point of fall, from the equation 
Dw) =" + D(0) 
= 1776 — 454 
= 1322, 
whence u= 468°6 m/s. 
From the above cited table we shall find 
A (U) = — 26°04 
L(G) = 04.969 
RD =2—=3 B12 
B(O)=— 276 
M(U)=— 00113 
A @) S BBG? 
LG) = ‘14715 
1/@) = 2°332 
Bi@) = 3°9441 
From the formule 
_ Caf A(u) — A(U) ) 
tan ¢ 5) LISD IOM} 
_ Ca § Ty) — 4) = 4(0) 
tim pe= FY Dl) DIDS 
= 
a cos O,. - 
i C£T(w) — T(U)} 
and 
— K7™0 Btu) - BU) _ 
Za K™VX ae mn uv) 
we shall obtain 
= 20745! 
é, =O mONh 
Ve = 469°2 m/s (1540 f/s) 
sie) OESeCse 
Z= 4:73 metres. 
In calculating the derivation 7, the coefficient K is found from the formula 
ree 2 
yh 1000 
where [eS SB 
c 
Ss == 530) 
h 
T 
= == tam 8°, 
since the angle of inclination of the rifling is 6° with Canet’s 6-inch gun. 
The coefficient K, entering in the formula for the derivation, ought to be deter- 
mined on the basis of results of firing in calm weather. Ordinarily the coefficient 
K, when found from experiment, comes out larger (approximately 13 times) than 
when calculated by the above deduced formula. 
